Question

find te area of the triangle ,two side of which are 18cm and 10cm and the perimeter is 48cm​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Perimeter of triangle = s+s+s

let tge unknown side be x

48 =18+10+x

48 = 28 +x

48 -28 = x

20 = x

semi perimeter = a+b+c/2

10+18+20/2 = 48/2 = 24

Area = √s( s-a)( s-b)( s-c)

√24 (24-18)(24-10)(24-20)

√24(6) (14) (4)

√2*2*2*3*2*3*2*7*2*2

2*2*3*2√7*2

24√14