find te value of k so that the equation (k+1)x2 +2(k+3)x+(k+8)=0 has real and equal roots.
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Answered by
1
type your question seriously.....what was that ....look at your ques...(k+3)×+(k+8) after the sign of multiplication ...+ is not allowed
mahesh4261:
it was not multiply it is written "X"
Answered by
0
you can do this question by using the formula:
1.b*b-4ac
2.x=b*b+_root mai b*b-4ac
1.b*b-4ac
2.x=b*b+_root mai b*b-4ac
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