Question

find te zeros of the polynkmial 4s²-4s+1​

Answer 1

Answer:

Given Quadratic equation :-

4s² - 4s + 1 = 0

4s²-2s-2s+1=0

2s(2s-1)-1(2s-1)=0

(2s-1)(2s-1)=0

s = 1/2 ; 1/2

Answer 2

Answer:

4s^2-4s+1=

4s^2-2s-2s+1=

2s(2s-1)-1(2s-1)=

(2s-1)(2s-1)

hence,s=1/2 and 1/2

please mark it as_brainliest answer please I am in need...

thank❣❤.....follow me guys