Question

find ten rational numbers between 2 and 3

Answer 1

Answer:

$\red {Required\: ten \: rational \: numbers\:are}$

$\green {\left( \frac{23}{11},\frac{24}{11},</p><p>\frac{25}{11},\frac{26}{11},\frac{27}{11},\frac{28}{11},\frac{29}{11},\frac{30}{11},\frac{31}{11}\right)}$

Step-by-step explanation:

$If \: we \:want \: to \:find \: ten \: rational \\numbers \: between \: 2 \: and \:3 ,then \: we \\write \: 2\:and \: 3\:as \: rational\:number \:with \\denominator\: 10+1 = 11$

$i.e \: 2 = \frac{2\times 11}{11} = \frac{22}{11}\\and \: 3 = \frac{3\times 11}{11}=\frac{33}{11}$

$2 = \frac{22}{11}<\left( \frac{23}{11},\frac{24}{11},</p><p>\frac{25}{11},\frac{26}{11},\frac{27}{11},\frac{28}{11},\frac{29}{11},\frac{30}{11},\frac{31}{11}\right)<\frac{33}{11}= 3$

Therefore.,

$\red {Required\: ten \: rational \: numbers\:are}$

$\green {\left( \frac{23}{11},\frac{24}{11},</p><p>\frac{25}{11},\frac{26}{11},\frac{27}{11},\frac{28}{11},\frac{29}{11},\frac{30}{11},\frac{31}{11}\right)}$

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Answer 2

Step-by-step explanation:

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