find ten rational numbers between -
2 and 3
Answers
Answer:
\green {\left( \frac{23}{11},\frac{24}{11}, < /p > < p > \frac{25}{11},\frac{26}{11},\frac{27}{11},\frac{28}{11},\frac{29}{11},\frac{30}{11},\frac{31}{11}\right)}(
11
23
,
11
24
,</p><p>
11
25
,
11
26
,
11
27
,
11
28
,
11
29
,
11
30
,
11
31
)
Step-by-step explanation:
\begin{gathered} If \: we \:want \: to \:find \: ten \: rational \\numbers \: between \: 2 \: and \:3 ,then \: we \\write \: 2\:and \: 3\:as \: rational\:number \:with \\denominator\: 10+1 = 11\end{gathered}
Ifwewanttofindtenrational
numbersbetween2and3,thenwe
write2and3asrationalnumberwith
denominator10+1=11
\begin{gathered} i.e \: 2 = \frac{2\times 11}{11} = \frac{22}{11}\\and \: 3 = \frac{3\times 11}{11}=\frac{33}{11}\end{gathered}
i.e2=
11
2×11
=
11
22
and3=
11
3×11
=
11
33
2 = \frac{22}{11} < \left( \frac{23}{11},\frac{24}{11}, < /p > < p > \frac{25}{11},\frac{26}{11},\frac{27}{11},\frac{28}{11},\frac{29}{11},\frac{30}{11},\frac{31}{11}\right) < \frac{33}{11}= 32=
11
22
<(
11
23
,
11
24
,</p><p>
11
25
,
11
26
,
11
27
,
11
28
,
11
29
,
11
30
,
11
31
)<
11
33
=3
Therefore.,
\red {Required\: ten \: rational \: numbers\:are}Requiredtenrationalnumbersare
\green {\left( \frac{23}{11},\frac{24}{11}, < /p > < p > \frac{25}{11},\frac{26}{11},\frac{27}{11},\frac{28}{11},\frac{29}{11},\frac{30}{11},\frac{31}{11}\right)}(
11
23
,
11
24
,</p><p>
11
25
,
11
26
,
11
27
,
11
28
,
11
29
,
11
30
,
11
31
)
Answer:
2.1,2.2,2.3,2.4,2.5,and 2.6 Are the rational number between 2 And 3 Hope It is helpful For you