Question

find ten rational numbers between -3\4 and 3\8

Answer 1

first we do denominator same then friction -6/8

and we multiply by 10 and divide by 10 both friction.
then friction becomes -60/80 and 30/80

ten friction becomes
-59/80,-58/80,-57/80,-56/80,-55/80,-54/80,-523/80,-52/80,-51/80,-50/80,-49/80.................. 28/80,29/80

I think, it is sufficient for u

Answer 2

$-\frac{6}{8},-\frac{5}{8},-\frac{4}{8},-\frac{3}{8},-\frac{2}{8},-\frac{1}{8},0,\frac{1}{8},\frac{2}{8},\frac{3}{8}$

Step-by-step explanation:

To find : Ten rational numbers between $-\frac{3}{4}$  and  $\frac{3}{8}$.

Solution :

First we make their denominator same,

Multiply and divide $-\frac{3}{4}$ by 2,

$-\frac{3\times 2}{4\times 2}=-\frac{6}{8}$

Now, the ten rational number between $-\frac{6}{8}$ and $\frac{3}{8}$.

$-\frac{6}{8},-\frac{5}{8},-\frac{4}{8},-\frac{3}{8},-\frac{2}{8},-\frac{1}{8},0,\frac{1}{8},\frac{2}{8},\frac{3}{8}$

#Learn more

Find ten rational numbers between -8/7 and 6/7

https://brainly.in/question/4585985