Question

find tension (T) and acceleration in system of block M1 and M2. ​

Answer 1

Answer:

first draw the free body diagram of the given figure

note the following

1)mass M

1

has its acceleration in upward direction

2)mass M

2

has its acceleration in downward direction

3)tension will remain same in both the string

now resolving the forces for both the block we find

T-M

1

gsinα=M

1

a

T-M

2

gsinβ=-M

2

a

hence we substitute the value of T in any of the following we get

T=M

1

a+M

1

gsinα

M

1

a+M

1

gsinα-M

2

gsinβ=-M

2

a

M

1

gsinα-M

2

gsinβ=-a(M

2

+M

1

)

a=

M

2

+M

1

M

2

gsinβ−M

1

gsinα