Question

Find :-

$\dfrac{2}{5} \times \dfrac{-3}{7} - \dfrac{1}{14} - \dfrac{3}{7} \times \dfrac{3}{5}$

Answer 1

Step-by-step explanation:

His total profit percentage is (100/3) or 33 and 1/3 percentage.

4kg faulty weight=3.6kg actual or correct weight.

1kg faulty weight=.9kg correct weight.

So the person is selling at the price of Rs 60 per .9 kg weight.

1kg correct weight apples selling price=60/.9=200/3 Rs

His gain per kg=(200/3)-50=(50/3)rupees

His total profit percentage =

(profit per kg/C.P per kg)*100={(50/3)/50}*100=(1/3)*100=100/3=33 and1/3 percent.

Make a question for this answer. xD

Answer 2

$\huge\pink{\mathtt{Solution :-}}$

$\red{\rightarrow\:}$ $\sf{\dfrac{2}{5}\times \dfrac{-3}{7} - \dfrac{1}{14} - \dfrac{3}{7} \times \dfrac{3}{5} = \dfrac{2}{5} \times \dfrac{-3}{7} -\dfrac{3}{7} \times \dfrac{3}{5} - \dfrac{1}{14}}$

(By Commutativity ↑)  

$\red{\rightarrow\:}$ $\sf{\dfrac{2}{5}\times \dfrac{-3}{7}  + (\dfrac{-3}{7} ) \times \dfrac{3}{5} - \dfrac{1}{14} }$

$\red{\rightarrow\:}$ $\sf{\dfrac{2}{5}\times \dfrac{-3}{7}  + (\dfrac{-3}{7} ) \times \dfrac{3}{5} - \dfrac{1}{14} }$

$\red{\rightarrow\:}$ $\sf{\dfrac{-3}{7} (\dfrac{2}{5} + \dfrac{3}{5} ) - \dfrac{1}{14}  }$

(By Distributivity ↑)

$\red{\rightarrow\:}$ $\sf{\dfrac{-3}{7}  \times 1-\dfrac{1}{14} = \dfrac{-6-1}{14} = \dfrac{-1}{2} }$

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