Math, asked by duragpalsingh, 11 months ago

Find:

I \ \displaystyle = \sf \int_0^{\frac{\pi}{6}} \dfrac{tan^4 \ x \ (tan^2 \ x - 2)}{(1-tan^2 \ x)^2} \ dx

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Answered by akanksha2614
4

Answer:

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Answered by Anonymous
4

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