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We know that integration of 1/√ ( a² - x² ) dx is
Sin-¹ x/a
______________________________
Integration of
x² dx
___________
√{ (a³)² - ( x³ )² }
=>
Put x³ = z
Differentiate both sides w.r.t x we get
3x² dx = dz
dx = dz/3x²
=>
integration of
x² dz
_____________
3x² { √ { (a³ )² - z² } }
=>
integration of
dz
_____________
3 { √{ (a³ )² - z² } }
=
1/3 { Sin-¹ ( z / a³ )
=
1/3 { Sin-¹ ( x³ / a³ ) + A
Where A is called constant of integration.
We know that integration of 1/√ ( a² - x² ) dx is
Sin-¹ x/a
______________________________
Integration of
x² dx
___________
√{ (a³)² - ( x³ )² }
=>
Put x³ = z
Differentiate both sides w.r.t x we get
3x² dx = dz
dx = dz/3x²
=>
integration of
x² dz
_____________
3x² { √ { (a³ )² - z² } }
=>
integration of
dz
_____________
3 { √{ (a³ )² - z² } }
=
1/3 { Sin-¹ ( z / a³ )
=
1/3 { Sin-¹ ( x³ / a³ ) + A
Where A is called constant of integration.
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