Find :
Anonymous:
put ( 1 + xe^x ) = z
Answers
Answered by
4
Heya!!
Put ( 1 + xe^x ) = z
xe^x = ( z -1 )
Differentiate both sides w.r.t x we get
e^x { 1 + x } dx = dz
=>
integration of
dz
________
xe^x ( z² )
=>
integration of
dz
_______
z² ( z - 1 )
=>
1/ { z² ( z - 1 ) =
A/{ z - 1 } + ( Bx + c ) / { z² }
Put ( 1 + xe^x ) = z
xe^x = ( z -1 )
Differentiate both sides w.r.t x we get
e^x { 1 + x } dx = dz
=>
integration of
dz
________
xe^x ( z² )
=>
integration of
dz
_______
z² ( z - 1 )
=>
1/ { z² ( z - 1 ) =
A/{ z - 1 } + ( Bx + c ) / { z² }
Answered by
0
Answer:
Change of Pronouns
Exercise 02
1. He said to me, "I write a letter."
2. He said to Sneha, "I am doing my work."
3. I said to him, "You have taken your turn." 4. I said to you, "Your chances of success are not bright."
5. We said to them, "You cannot get the posts you aspire for." 6. He said to me, "You did not admit your mistake."
7. Ram says to me, "You should mind your own business."
8. Sweta said to Anshu, "I am a good girl."
9. I said to her, "He is a good player."
10.Rekha said to Madan, "I was going to you."
Step-by-step explanation:
plz answer my question bro plz
Similar questions