Find term from the end in
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Given, ( x + 1/x)^2n+1
Number of the terms = 2n + 2
(p + 2 ) terms from the last =
(2n + 2) - (p+ 2) +1
=(2n - p + 1)
term from starting
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Step By Step Explanation
Here, we have →
The expansion of has (2n+1) terms.
So, term from end →
term from beginning
i.e term.
Now, we have →
generalRd:
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