Question

find
$x {}^{2} \: + \frac{1}{x {}^{2} }$
where
$x + \frac{1}{x} = 6$

Answer 1

find
$x {}^{2} \: + \frac{1}{x {}^{2} }$
where
[tex]x + \frac{1}{x} = 6[/t
what's question

Answer 2

x²+1/x²=?



x+1/x=6
Squaring both side
(x+1/x)²=6²
x²+1/x²+2=36
x²+1/x²=36-2
x²+1/x²=34