Question

find tge areaof the shaded region given below?​

Answer 1

lets start from the bottom,

area of rect= l×b

= 18m×3m

= 54m²

Now the slope which is in a shape of parallelogram

area= b×h

= 10m×3m

= 30m²

Now, in the top quadrilateral, draw a line from the end of 12m to the top such that the top is perpendicular to that line

Now area of that rect= l×b

= 12m× 3m

= 36m²

The remaining portion is a∆ with base 3m and h(18-12)m= 6m

Area of a∆= 1/2(b×h)

= 1/2(3m×6m)

= 3m×3m

= 9m²

Therefore, the total area=54m²+30m²+36m²+9m²

=129m²