Question

find tge attitude of a triangle whose base is 20 cm and area is 150cm square​

Answer 1

Answer:

Altitude = 15 cm

Step-by-step explanation:

Area = 1/2 base × height

150 = 1/2 × 20 × h

h = 15 cm

Answer 2

★ Given :

• Triangle base is 20 cm
• Area of triangle is 150 cm

★ To Find :

• Altitude of triangle ?

★ Formula used :

$\sf{:\implies Area_{(triangle)} = \frac{1}{2} \times b \times h}$

Here,

⠀⠀⠀⠀B is the Base of triangle, H is the Height of triangle and A is the Area of triangle, And here in this question we have A = 150 cm & B = 20 cm.

⠀

By using the required formula and substituting all the given values in the formula, we get :

$\begin{gathered}\sf{:\implies \mathcal{A}rea_{(triangle)} =\frac{1}{2} (b \times h)} \\ \\ \\ \sf{:\implies \mathcal150= \frac{1}{ \cancel 2} \times \cancel{20} \times h } \\ \\ \\ \sf{ : \implies \mathcal150 = 10 \times h} \\ \\ \\ \sf{:\implies \frac{15 \cancel0}{1 \cancel0 }= h} \\ \\ \\ \sf{ :\implies{ \boxed{ \red{ \sf{15 = h}}} }} \end{gathered}$

$\sf{\therefore \underline{The\: Height\: of\: triangle\:is\: 15\: cm}}$

$\sf{ \pink{ \underline{Verification}}}$

We have,

• Base = 20 cm
• Height = 15 cm
• Area = 150 cm

$\begin{gathered}\sf{:\implies \mathcal{A}rea_{(triangle)} = \frac{1}{2} (b \times h)} \\ \\ \\ \sf{:\implies \mathcal150= \frac{1}{ \cancel 2} \times \cancel{20} \times 15} \\ \\ \\ \sf{ : \implies \mathcal150 = 10 \times 15} \\ \\ \\ \sf{:\implies 150 = 150}\end{gathered}$

$\sf{ \blue{ \underline{ Hence\:Verified}}}$

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