find tge csa of cone whose radius 3cm and slant height 0.2
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We have,
r = 3 cm
h = 4 cm
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Let l be the slant height of the cone. Then,
\qquad \tt \: {l}^{2} = {r}^{2} + {h}^{2} \\ \\ \implies \tt { l }^{2} = {3}^{2} + {4}^{2} \\ \\ \implies \tt \: l = \sqrt{25} \: cm = 5 \: cm \\ \\
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\therefore Area of the curved surface = πrl
\red\rightarrow \tt \: ( \frac{22}{7} \times 3 \times 5) \: {cm}^{2} = 47.14 \: {cm}^{2}
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