Find tge least among three consecutive integers whose sum is 51
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Let the smallest of three consecutive number be x, thus other two consecutive numbers be x + 1 and x + 2.
As per the statement, sum of these three consecutive numbers is 51. As such
x + x + 1 + x + 2 = 51
3x + 3 = 51
3x = 51 - 3
3x = 48
x = 48/3
x= 16
The smallest of three consecutive number is 16. Other two numbers are
x + 1 = 16 + 1 = 17
x + 2 = 16 + 2 = 18
Thus three consecutive numbers are 16, 17 and 18
Answer three consecutive numbers are 16, 17 and 18
Let us check the correctness of answer by taking the sum of derived numbers, which should be 51.
16 + 17 + 18 = 51
51 = 51
Means answer is correct
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Step-by-step explanation:
So the three numbers whose sum is 51 are 16, 17 and 18.
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