Math, asked by pradhansukanti938, 7 months ago

Find tge least among three consecutive integers whose sum is 51​

Answers

Answered by karansaw14366
1

Let the smallest of three consecutive number be x, thus other two consecutive numbers be x + 1 and x + 2.

As per the statement, sum of these three consecutive numbers is 51. As such

x + x + 1 + x + 2 = 51

3x + 3 = 51

3x = 51 - 3

3x = 48

x = 48/3

x= 16

The smallest of three consecutive number is 16. Other two numbers are

x + 1 = 16 + 1 = 17

x + 2 = 16 + 2 = 18

Thus three consecutive numbers are 16, 17 and 18

Answer three consecutive numbers are 16, 17 and 18

Let us check the correctness of answer by taking the sum of derived numbers, which should be 51.

16 + 17 + 18 = 51

51 = 51

Means answer is correct

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Answered by darkwader
1

Step-by-step explanation:

So the three numbers whose sum is 51 are 16, 17 and 18.

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