Question

find tge local maximum and minimum value of f(x)=2x³+3x²-36x using both 1st and 2nd derivative test .find tge intervqls on which increasing, decreasinv ,concavity , inflection point​

Answer 1

Answer:

Here's the process, numbers and all:

Find f'(x) using the power rule.

f(x)=2x3−3x2−36x−3

f'(x)=6x2−6x−36

The local minima and maxima will occur when the derivative equals 0:

6x2−6x−36=0

x2−x−6=0

(x−3)(x+2)=0

x=3 , x=−2

Step-by-step explanation:

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