Math, asked by MOIZQUADRI, 11 months ago

find th 20th and nth terms of the gp 5/2,5/4,5/8,......

Answers

Answered by kar13
5
it is your answer thanks for your
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Answered by Anonymous
8

 \large  \underline{ \underline{ \sf \: Solution : \:  \:  \: }}

Given ,

 \starFirst term (a) = 5/2

 \starCommon difference (r) = 1/2

We know that , nth term of GP is

 \large \sf \fbox{ \fbox{ a_{n} = a {(r)}^{n  - 1}} }

So , 20th term of the given GP :

 \sf \implies  a_{20} =  \frac{5}{2}  \times  {( \frac{1}{2} )}^{20 - 1}  \\  \\  \sf \implies   a_{20} =  \frac{5}{2}   \times  { (\frac{1}{2}) }^{19}  \\  \\   \sf \implies    \fbox{ a_{20}  =  \frac{5}{ {(2)}^{20} } }

n term of the given GP :

 \sf \implies  \fbox{a_{n} = \frac{5}{2}  \times  {( \frac{1}{2} )}^{n - 1} }

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