Find th e value of k if x-2 is a factor of 2x²-6x²+5x+k.
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Answered by
1
x - 2 = 0
x = 2
p(2) =2x² - 6x²+5x +k
=> 2× 2² - 6×2² + 5×2+k
=>8 - 24 + 10 +k
=> 18-24 +k
k = 6 Answer
x = 2
p(2) =2x² - 6x²+5x +k
=> 2× 2² - 6×2² + 5×2+k
=>8 - 24 + 10 +k
=> 18-24 +k
k = 6 Answer
Answered by
2
If x-2 is a factor then x-2 = 0
x = 2
P(x) = 2x²-6x²+5x+k = 0
P(2) = -4x²+5x+k = 0
-4*2 + 5*2 + k = 0
-8 + 10 + k = 0
2 + k = 0
k = -2
Hope this helpz :)
x = 2
P(x) = 2x²-6x²+5x+k = 0
P(2) = -4x²+5x+k = 0
-4*2 + 5*2 + k = 0
-8 + 10 + k = 0
2 + k = 0
k = -2
Hope this helpz :)
Fawzan10:
-4 * 4 + 5 * 2 + k = 0
-16+10+k = 0
-6 + k = 0
k = 6
Sorry
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