find th unit vector perpendicular to plane of A =2i-6i-3k and b=41 3j -k
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Answer:
(a) We add the components of the three vectors
D
=
A
+
B
+
C
=6
i
^
−2
j
^
∣
D
∣=
6
2
+2
2
=6.32m at θ=342
0
(b) Again, using the components of the three vectors
E
=−
A
−
B
+
C
=−2
i
^
+12
j
^
∣
E
∣=
2
2
+12
2
=12.2m at θ=99.5
0
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