Find th value of a and b such that (√3+1)/(√3-1)=a+b√3
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a=2 and b=1
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(√3+1)/(√3-1)
={(√3+1)×(√3+1)}/{(√3-1)×(√3+1)}
={(√3+1)^2}/{(√3)^2-(1)^2}
={(√3)^2+2√3.1+1^2}/3-1
={3+2√3+1}/2
=4+2√3/2
=2+√3
a=2,b=1
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