find tha AP whose 3rd term is 5 and 7th term is 9
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a+(n-1)d=an
a+2d=5 eq-1
a+6d=9 eq-2
subtracting
a+2d-a-6d=5-9
-4d=-4
d=1
substituting the value of d=1
a+2=5
a=3
A.P =3,4,5,6,7,8............
a+2d=5 eq-1
a+6d=9 eq-2
subtracting
a+2d-a-6d=5-9
-4d=-4
d=1
substituting the value of d=1
a+2=5
a=3
A.P =3,4,5,6,7,8............
sk12385:
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