Question

find tha base of this question

Answer 1

area of isosceles Δ =( a/4)(√4b²-a²)
base-a
side-b

area of the Δ given=12cm²

⇒ ( a/4)(√4b²-a²)=12
(a/4)(√4(25)-a²)=12
(a/4)(√100-a²)=12
a(√100-a²)=48
(√100-a²)=48/a

squaring both sides

100-a²=2304/a
-a²=(2304/a²)-100
a²=100-(2304/a²)
a⁴=2304-100a²
a⁴-100a²=2304

by solving this equation, you will get your answer...............