Question

find tha domain and range of the function f(x)=√9-x²

Answer 1

for domain
$\sqrt{9 - x {}^{2} } \geqslant 0 \\ 9 - {x}^{2} \geqslant 0 \\ {x}^{2} \leqslant 9 \\ - 3 \leqslant \: x \leqslant 3$
this is domain



now range
$sinc e\: \sqrt{} is \: always \: positive \: hence \: range \: i s \\ 0 \leqslant x < \infty$

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Answer 2

Answer:

Step-by-step explanation:

Domain:-(3,3)

Range:(0,3)