Question

Find tha eleventh term from that last term of tha Ap 27,23,19......,-65

Answer 1

Rewrite the A..P ,

- 65 , - 61 , - 57 , ... 19 , 23 , 27

here ,

first term = a = - 65

common difference = a2 - a1

d = - 61 - ( - 65 )

d = -61 + 65

d = 4

n = 11

nth term = an = a + ( n - 1 )d

a11 = -65 + ( 11 - 1 ) 4

= -65 + ( 10 × 4 )

= -65 + 40

= -25

Therefore ,

required 11th term = a11 = - 25

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Answer 2

Given AP is :-
27,23,19......,-65
We have to find 11th term from end
We will
Reverse the AP to simplify it .
Thus the new AP will be
-65,-61,............19,23,3 27

Now here
a = -65
an = 27
d = -61-(-65) => 4
Now,
We know an = a+(n-1)d
Here ATQ we have to find 11th term therefore
n = 11
so, a11 = -65+(11-1)4
=> -65+40
=> -25
hence 11th last term will be -25