Question

find tha h.c.f of 2312 and 3434 using continued division method​

Answer 1

Answer:

The HCF of 2312 and 3434 is 34

Answer 2

Answer:

34 is the HCF of 2312 and 3424 .

Step-by-step explanation:

Finding maximum not unusualplace factor (H.C.F) through top factorization for big range isn't always very convenient.

• The technique of lengthy department is extra beneficial for big numbers.
• In this technique we first divide the extra range through the smaller range.
• The the rest turns into the brand new divisor and the preceding divisor as the brand new dividend.
• We retain the method till we get zero the rest.

We use the repeated department technique for locating maximum not unusualplace factor (H.C.F) of or extra numbers.

• Step I: Divide the large number by the smaller one.
• Step II: Then the remainder is treated as divisor and the divisor as dividend.
• Step III: Divide the first divisor by the first remainder.
• Step IV:Divide the second divisor by the second remainder.
• Step V:Continue this process till the remainder becomes 0.

2312√ 3434 (1

2312

______

1122 √ 2312 ( 2

2244

______

68 √ 1122 ( 16

1088

______

34 √ 68 ( 2

68

____

0

_____

(#SPJ2)