find tha linear relation between x and y such that p(x, y). is equidistant from the points A(1, 4) and b (-1, 2)
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Step-by-step explanation:
Let P(x,y) be equidistant from points A(1,4) and B(-1,2)
According to question AP = BP
AP^2 = BP^2
Using distance formula
(X-1)^2 + (Y-4)^2 = (X+1)^2 + (Y-2)^2
-4x - 4y = -12
x + y = 3
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