Find tha smallest number which divided by 25,40 and 60 leaves remainder 7 in each case
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required no.=lcm of (25,40,60)+7
LCM OF 25 , 40 , 60 = 5^2
=2^3×5
=2^2×3×5
LCM = 600
Required no. = 600+7
=607
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