find tha value of a and b for which following system of eqn kas infinity no. of solution 2x +3y=7 (a+b)x - (a+b-3)y = 4a +b
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Here is your answer,
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2x + 3y = 7
(a+b)x - (a+b-3)y = 4a + b
For infinite solutions : a₁ = b₁ = c₁
a₂ b₂ c₂
2 = 3 = 7
(a+b) (a+b-3) 4a+b
2 = 3
a+b a+b-3
2a+2b-6 = 3a+3b
a + b = -6 -----------------(i)
2 = 7
a+b 4a+b
8a+2b = 7a+7b
a = 5b
Put a = 5b in (i)
5b + b = -6
6b = -6
b = -1
Put b = -1 in (i)
a -1 = -6
a = -5
Ans: a = -5 and b = -1.
______________________________________________________________
Hope this helped you !!
Please mark as brainliest !!
Here is your answer,
______________________________________________________________
2x + 3y = 7
(a+b)x - (a+b-3)y = 4a + b
For infinite solutions : a₁ = b₁ = c₁
a₂ b₂ c₂
2 = 3 = 7
(a+b) (a+b-3) 4a+b
2 = 3
a+b a+b-3
2a+2b-6 = 3a+3b
a + b = -6 -----------------(i)
2 = 7
a+b 4a+b
8a+2b = 7a+7b
a = 5b
Put a = 5b in (i)
5b + b = -6
6b = -6
b = -1
Put b = -1 in (i)
a -1 = -6
a = -5
Ans: a = -5 and b = -1.
______________________________________________________________
Hope this helped you !!
Please mark as brainliest !!
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