Question

find tha value of a,b and c for this 5x2-22x=15 equadratic equation​

Answer 1

Answer:

mark as brainalist

Step-by-step explanation:

Supplement : Solving Quadratic Equation Directly

Solving 5x2-22x-15 = 0 directly

Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula

Parabola, Finding the Vertex:

4.1 Find the Vertex of y = 5x2-22x-15

Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 5 , is positive (greater than zero).

Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) ola has indeed two real solutions.

Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.

For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is 2.2000

Plugging into the parabola formula 2.2000 for x we can calculate the y -coordinate :

y = 5.0 * 2.20 * 2.20 - 22.0 * 2.20 - 15.0

or y = -39.200

Parabola, Graphing Vertex and X-Intercepts :

Root plot for : y = 5x2-22x-15

Axis of Symmetry (dashed) {x}={ 2.20}

Vertex at {x,y} = { 2.20,-39.20}

x -Intercepts (Roots) :

Root 1 at {x,y} = {-0.60, 0.00}

Root 2 at {x,y} = { 5.00, 0.00}

Solve Quadratic Equation by Completing The Square

4.2 Solving 5x2-22x-15 = 0 by Completing The Square .

Divide both sides of the equation by 5 to have 1 as the coefficient of the first term :

x2-(22/5)x-3 = 0

Add 3 to both side of the equation :

x2-(22/5)x = 3

Now the clever bit: Take the coefficient of x , which is 22/5 , divide by two, giving 11/5 , and finally square it giving 121/25

Add 121/25 to both sides of the equation :

On the right hand side we have :

3 + 121/25 or, (3/1)+(121/25)

The common denominator of the two fractions is 25 Adding (75/25)+(121/25) gives 196/25

So adding to both sides we finally get :

x2-(22/5)x+(121/25) = 196/25

Adding 121/25 has completed the left hand side into a perfect square :

x2-(22/5)x+(121/25) =

(x-(11/5)) • (x-(11/5)) =

(x-(11/5))2

Things which are equal to the same thing are also equal to one another. Since

x2-(22/5)x+(121/25) = 196/25 and

x2-(22/5)x+(121/25) = (x-(11/5))2

then, according to the law of transitivity,

(x-(11/5))2 = 196/25

We'll refer to this Equation as Eq. #4.2.1

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

(x-(11/5))2 is

(x-(11/5))2/2 =

(x-(11/5))1 =

x-(11/5)

Now, applying the Square Root Principle to Eq. #4.2.1 we get:

x-(11/5) = √ 196/25

Add 11/5 to both sides to obtain:

x = 11/5 + √ 196/25

Since a square root has two values, one positive and the other negative

x2 - (22/5)x - 3 = 0

has two solutions:

x = 11/5 + √ 196/25

or

x = 11/5 - √ 196/25

Note that √ 196/25 can be written as

√ 196 / √ 25 which is 14 / 5

Solve Quadratic

Answer 2

Answer:

$a=5\\b=-22\\c=-15$

Step-by-step explanation:

This is a quadratics equation which can be solved by the rules of Sridhar Acharya.

The formula of Sridhar Acharya is

$\ \ \ \ \ \frac{-b+-\sqrt{b^{2}-4ac } }{2a}$

According to this formula we can calculate the roots of x as well as the values of a,b, and c

first of all we need to write the equation in a proper manner. like that

$5x^{2} -22x=15$

to solve any kind of the quadratic equation we need to write the equation as a manner that the equation always equals to zero.

so,

$5x^{2} -22x-15=0$

according to Sridhar Acharya rules

a is the part which is attached to the $x^{2}$

b is the part which is attached to the $x$

c is the part which is alone and without any variables

so here,

$a=5\\b=-22\\c=-15$