Question

Find tha value of a, if the equation x²-4x+a=0 has no real roots

Answer 1

thanks here is your answer.

Hindustan jindabaad

Answer 2

Answer:

Step-by-step explanation:

x^2-4x+a = 0

Comparing with ax^2 + bx + c= 0

a = 1 b = -4. c= a

b^2 -4ac < 0. ........equation has no real roots

(-4)^2 - 4(1)(a) < 0

16 -4a < 0

16 < 4a

4< a

a > 4

So, the value of a is greater than 4

HOPE IT HELPS YOU!!