Find that point on x-axis which is equidistant from points (-2,-5)and (2,-3)
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Answer:
Step-by-step explanation:
on x-axis point y is always zero
therefore let the point is (a,0) and are equidistant from the given points
using distance formula and equate it
√((-5-0)²+(-2-a)²) = √((-3-0)²+(2-a)²)
25+4+a²+2×2a = 9+4+a²+2×(-2a)
29+4a=13-4a
8a=16
a=2
therefore the point on x- axis which is equidistant from the given point is (2,0)
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