Find that value of (2•3a^5b^2)×(1•2a^2b^2)'when a=1and b=0•5
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Based on expansion of ( a + b ) 2 1 . Expand ( 0 ) ( 3x + 273 m ( a + b ) - 0 + 6 . Simplify ... ( i ) ( 3a + 2b + 4c ) 2 ( ii ) ( 2a + 3b – c ) 2 ( iii ...
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