Question

Find that value(s) of x for which the distance between the points P(x, 4) and Q(9, 10) is 10 units. (2011D)

class 10 chapter 7​

Answer 1

Answer:

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Answer 2

Answer:

Given:-

Points P(x,4),Q(9,10) and PQ=10

Distance formula: PQ=(x2−x1)2+(y2−y1)2

PQ2=(x2−x1)2+(y2−y1)2

100=(9−x)2+(10−4)2

=81+x2−18x+36

=117+x2−18x

100=117+x2−18x

x2−18x+17x=0 (solve this equation)

(x−1)(x−17)

x=1 or x=17.