Find that values of x for which the distance between the point p(x,4) and q(9,10) is 1o units.
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⇒ (PQ)2 = (10 units)2 = 100 units2
⇒ (9 – x)2 + (10 – 4)2 = 100
⇒ 81 – x2 – 18x + 36 = 100
⇒ x2 – 18x + 17 = 0
⇒ (x – 1) (x – 17) = 0
⇒ x = 1 or x = 17
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