Question

find the 0 of the polynomial 2x-2+√3​

Answer 1

Hey ! 

2x² - 3x - 2 =0 

=> 2x² - 4x + x - 2 =0 [Using Spliting method) 

=> 2x ( x - 2) +1 ( x - 2) = 0 

=> ( 2x + 1 ) ( x - 2) = 0 

2x + 1 = 0 

x = - 1/2 

and 2nd , x = 2 

Hence there is two zero , - 1/2 and 2 

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2nd solution ..........

2x^2-3x-2=0
2x^2-4x+x-2=0
2x(x-2)+1(x-2)=0
(x-2)(2x+1)=0
x-2=0
x=2
2x+1=0
2x=-1
x=-1/2
x=2,-1/2 are answers

Answer 2

Answer:

$x = \frac{2 - \sqrt{3} }{2}$

Step-by-step explanation:

=> 2x-2+√3=0

=> 2x=2- √3

=> x= (2-√3) / 2

ans