Question

find the 0s of the following quadratic polynomial and verify the relationship between the 0s and it's coefficient x2 -2x-8





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Answer 1

Answer:

x²-2x-8

factors of 8 is 2×4

x²+2x-4x-8

x(x+2) -4(x+2)

(x-4) (x+2)

x= 4,x=-2

$\alpha = 4 \: and \: \beta = - 2$

verification of relationship

$\alpha + \beta = \frac{ - b}{a}$

4+(-2) = -(-2/1)

2= 2 -------------------------i

$\alpha \times \beta = \frac{c}{ a}$

4(-2) =-8/1

-8= -8 -----------------------ii

from eq i and ii we varified the relationship of zeros and coefficient

Answer 2

Step-by-step explanation:

x²-2x-8

factors of 8 is 2×4

x²+2x-4x-8

x(x+2) -4(x+2)

(x-4) (x+2)

x= 4,x=-2

\alpha = 4 \: and \: \beta = - 2α=4andβ=−2

verification of relationship

\alpha + \beta = \frac{ - b}{a}α+β=

a

−b

4+(-2) = -(-2/1)

2= 2 -------------------------i

\alpha \times \beta = \frac{c}{ a}α×β=

a

c

4(-2) =-8/1

-8= -8 -----------------------ii

from eq i and ii we varified the relationship of zeros and coefficient