find the 1 term and common ratio of the gp whose 6 th term and 11 th term are 192 and 6144 respectively
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ar^(6-1) = ar^5 = 192
ar^(11-1) = ar^10 = 6144
ar^5 × r^5 = 6144
Putting value of ar^5 we get
192 × r^5 = 6144
Solving we get
r = 2
Putting value of s in ar^5 = 192 we get
a = 6 which is the first term
ar^(11-1) = ar^10 = 6144
ar^5 × r^5 = 6144
Putting value of ar^5 we get
192 × r^5 = 6144
Solving we get
r = 2
Putting value of s in ar^5 = 192 we get
a = 6 which is the first term
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