Find the 10 term from the last term of the A.P 3,8,13---------253
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you can use this formula
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Solution:
a = 3, d = 5
we have to find from end then write the AP from end
253, 248, 243, ......., 3
For this AP
a= 253
d = 248-253 =-5
an=a+ (n-1)d
a10=253+(10-1)(-5)
a10=253+9(-5)
a10=253-45
a10=208
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