Find the 10 term from the last tetm of the A.P 3,8,13...253
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Answered by
3
after reversing the AP we get the new AP as:
253,248,243,.......13,8,3
here
a= 253
d= -5
n= 10
A10= a+(n-1)d
A10= 253-45
A10= 208
hope it helps you
253,248,243,.......13,8,3
here
a= 253
d= -5
n= 10
A10= a+(n-1)d
A10= 253-45
A10= 208
hope it helps you
Arjunaksd:
so k kya kregi
Answered by
1
here is your answer dude hope that it will help u
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