find the 10 term of an A.P. 2,7,12.........
Answers
Answered by
6
a=2,d=7-2=5,n=10
an=a+(n-1)d
an=2+(10-1)5
an=2+(9)5
an=2+45
an=47
an=a+(n-1)d
an=2+(10-1)5
an=2+(9)5
an=2+45
an=47
ankitsinghgame:
a=2
an=47
An=47
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Answered by
4
Hey there!
Here,
First term, a = 2
Common difference, d = 7 - 2 = 5
No. of terms, n = 10
As we know,
Sum of nth term = a + (n-1)d
= 2 + (10-1)5
= 2 + 9(5)
= 2 + 45
= 47
Hence,
10th term of the A.P. is = 47
Cheers!
Here,
First term, a = 2
Common difference, d = 7 - 2 = 5
No. of terms, n = 10
As we know,
Sum of nth term = a + (n-1)d
= 2 + (10-1)5
= 2 + 9(5)
= 2 + 45
= 47
Hence,
10th term of the A.P. is = 47
Cheers!
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