Question

find the 10 term of the Ap whose sum of n terms is given by 2nsquare+3n

Answer 1

given Sn=2n^2+3n
we know
tn=Sn-S (n-1)
=2n^2+3n-2 (n-1)^2-3 (n-1)
=4n+1
now 10th term of AP is
t10=4 x 10+ 1=41

Answer 2

nth term=Sn - S(n-1)
=2n^2+3n -[2(n-1)^2+3(n-1)]
=2n^2+3n-2n^2-2+4n-3n+3
nth term=4n+1
10th term=40+1=41