find the 10 th term in the binomial expansion (a/b-2b/a^2)^12
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Given in the question an expression
(a/b-2b/a^2)^12
To find the 10th term of above expression we will use following formula
nCr (2x²)^(n-r) (1/x)^(r)
Where n=12
r=10
12C10 (2x²)^2 (1/x)^10
66 (4x^4) (1/x^10)
264 (x^4) (1/x^10)
We will apply power product rule
264 (x^ (4-10))
The 10th term in the binomial expansion of (a/b-2b/a^2)^12 = 264(x^-6)
Hope my answer will help you....
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