Question

find the 10 th term of the Ap whose sum of n terms is given by 2n^2+3n​

Answer 1

hope it helps you........................

Answer 2

Answer:

See below.

Step-by-step explanation:

given,

$s_{n}$ = 2$n^{2}$ + 3$n^{}$

we know, for $n^{th}$ term of an AP,

$a_{n}$ =  $s_{n}$ - $s_{n-1}$

$a_{10}$  = $s_{10}$ - $s_{9}$         (For $s_{10}$, $n^{}$ = 10,  and for $s_{9}$,  $n^{}$ = 9)

     = {2 (10×10) + 3×10} - {2(9×9) + 3×9}

     = (200+30) - (162 + 27)

     = 230 - 189

     = 41

Answer = 41