Find the 10 th term of the sequence√3,√2,√24...
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a = √3 , d= √2-√3
An = a+(n-1)d
A¹⁰ = √3 + (10-1)(√2-√3)
A¹⁰ = √3 + 9√2 -9√3
A¹⁰ = 9√2 -8√3
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