Question

find the 10 th term of the sequence -6,-11/2,-5
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Answer 1

Answer:

a= –6

d= –11/2–(–6)

= –11/2+6

= (–11+12)/2

= 1/2

n=10

a n = a+(n–1)d

= –6+(10–1)1/2

= –6+9/2

=(–12+9)/2

= –3/2

Therefore, the 10th term of the sequence –6,–11/2,–5 is –3/2