Question

Find the 100th term and nth term for -1, -2, and -3 (ALGEBRA) plsss I will give brainliest

Answer 1

$a_1=-1\\d=-1\\\\a_n=a_1+(n-1)d\\a_n=-1+(n-1)\cdot(-1)\\a_n=-1-n+1\\a_n=-n\\\\a_{100}=-100$

Answer 2

Answer:

Step-by-step explanation:

Here a1=(-1) , a2=(-2), a3=(-3)

And d=a2-a1

So d= -2 - (-1)= -1

For 100th term

Tn=a+(n-1)d

T100 = -1 + (100-1)(-1)

T100 = -1 + 99(-1)

T100 = -1-99

T100 = -100

For nth term

a(n)= a+(n-1)d

a(n)= -1+(n-1)(-1)

a(n)= -1 -n +1

a(n)= -n