Math, asked by chinnu7971, 3 months ago

Find the 100th term for the following series 6,11,16,21,26,31.

Answers

Answered by arun26114

0

Answer:

501

Step-by-step explanation:

a100=a1+(n-1)d

a100=6+(100-1)5

a100=6+99×5

a100=6+495

a100=501

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