Math, asked by Raj4566, 1 year ago

find the 101st term of A.P 5, 11, 17​


dhruvvayakul07: hi
dhruvvayakul07: heres u r ans
dhruvvayakul07: t1=5 t2=11 t3=17
dhruvvayakul07: so. d=t2-t1 so d =6
dhruvvayakul07: so, tn=a+(n-1)d
dhruvvayakul07: so, t101=5+(101-1)6
dhruvvayakul07: so, t101=5+100×6
dhruvvayakul07: ...t101=5+600 so, 《t101=605 》that is u r ans

Answers

Answered by Agastya0606
1

The 101st term of the A.P is 605.

Given,

An arithmetic progression 5, 11, 17,...

To Find,

The 101st term of the A.P.

Solution,

The formula for calculating the nth term of an A.P is

aₙ = a+(n-1)d

In the given A.P

a = first term of the A.P = 5

d = common difference = 11-5 = 6

n = 101

Now,

a₁₀₁ = a+(101-1)d

a₁₀₁ = 5+(100)6

a₁₀₁ = 5+600 = 605

Hence, the 101st term of the A.P is 605.

#SPJ3

Answered by tiwariakdi
1

Given :

  • given A.P is 5 , 11 , 17 ...
  • first term a1 = a = 5

to find : 101th term  

solution :

nth term of A.P is an   = a+(n-1)d\\

d = common difference = a2 - a1

d=11-5=6\\

n = 101

= > an=a+(n-1)d\\= > a101=5+(101-1)6\\= > a101= 605

Hence , 101st term of given A.P is 605

#SPJ2

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